序列问题 文章来源: 乱弹 于 2005-09-13 20:02:21 Find all k>0 such that for all sequence {a(n)} satisfying a(n+2)=ka(n+1)-a(n) whenever n>0, we always have a(n+8)=a(n) for all n.
序列问题
海姑娘 (2005-10-06 04:40:18) 评论 (0)序列问题 文章来源: 乱弹 于 2005-09-13 20:02:21 Find all k>0 such that for all sequence {a(n)} satisfying a(n+2)=ka(n+1)-a(n) whenever n>0, we always have a(n+8)=a(n) for all n.